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  4. A 50 W bulb connected in series with a heater coil is put to an AC mains. Now the bulb is replaced by a 100 W bulb. The heater output will

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Q. A $50 \,W$ bulb connected in series with a heater coil is put to an $AC$ mains. Now the bulb is replaced by a $100 \,W$ bulb. The heater output will

Current Electricity

Solution:

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$P_{1}=\left(\frac{E}{R+R'}\right)^{2} R'$
$P_{2}=\frac{E R'}{\left(\frac{R}{2}+R'\right)^{2}}$
$P_{2} > P_{1}$