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Q. A $50\, mH$ coil carries a current of $2\, A$. The energy stored, in joules, is

Electromagnetic Induction

Solution:

Energy stored, $E=\frac{1}{2} L i^{2}$
$=\frac{1}{2} \times 50 \times 10^{-3} \times 4=0.1\, J$