Question

A $50 \, kg$ girl wearing high heel shoes balances on a single heel. The heel is circular with a diameter of $1.0 \, cm$ . What is the pressure exerted on the horizontal floor?

• A. $6.24\times 10^{6}Pa$
• B. $5.63\times 10^{7}Pa$
• C. $4.81\times 10^{6}Pa$
• D. $7.19\times 10^{7}Pa$

Answer 1

Answer: (A)

Given, mass of girl (m) = 50 kg
Diameter of circular heel (2r) = 1.0 cm
Radius (r) = 0.5 cm
= 5 × 10^-3 m
Area of the circular heel (A) = πr²
= 3.14 × (5 × 10^-3)² m²
$=78.50\times 10^{- 6}m^{2}$
The pressure exerted on the horizontal floor
$P=\frac{F}{A}=\frac{m g}{A}$
$=\frac{50 \times 9 .8}{78 .50 \times 10^{- 6}}$
$=6.24\times 10^{6}Pa$