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Q. A $50\, Hz$ AC current of crest value $1\, A$ flows through the primary of a transformer. If the mutual inductance between the primary and secondary be $0.5\, H$, the crest voltage induced in the secondary is

AIIMSAIIMS 2014

Solution:

$d i=2-(1-1) =2 A$
$d t =\left(\frac{1}{100}\right)$
$M =0.05\, H$
$e =M \frac{d i}{d t}=0.5\left(\frac{2}{1 / 100}\right)=0.5 \times 2 \times 100$
$e =100\, V$