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Chemistry
A 5 % solution of cane sugar (M.W. = 342) is isotonic with 1 % solution of substance X. The molecular weight of X is
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Q. $A \,5\%$ solution of cane sugar $(M.W. = 342)$ is isotonic with $1\%$ solution of substance $X$. The molecular weight of $X$ is
Solutions
A
$171.2$
0%
B
$68.4$
100%
C
$34.2$
0%
D
$136.2$
0%
Solution:
Being isotonic, molar concentration of cane sugar = molar concentration of substance $X$
$\frac{5}{342} \times \frac{1000}{100}$
$= \frac{1}{x} \times \frac{1000}{100}$
(let the molecular weight of $X = x$)
$x = \frac{342}{5} = 68.4$