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  4. A 5 -metre long wire is fixed to the ceiling. A weight of 10 kg is hung at the lower end and is 1 metre above the floor. The wire was elongated by 1 mm. The energy stored in the wire due to stretching is

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Q. A $5$ -metre long wire is fixed to the ceiling. A weight of $10\, kg$ is hung at the lower end and is $1$ metre above the floor. The wire was elongated by $1\, mm$. The energy stored in the wire due to stretching is

Mechanical Properties of Solids

Solution:

$W =\frac{1}{2} \times F \times l$
$=\frac{1}{2} m g l=\frac{1}{2} \times 10 \times 10 \times 1 \times 10^{-1}$
$=0.05\, J$