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  4. A 5 kg brick of 20 cm × 10 cm × 8 cm dimensionless lying on the largest base. It is now made to stand with length vertical. If g=10 ms -2, then the amount of work done is

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Q. A $5\, kg$ brick of $20 \,cm \times 10 \,cm \times 8 \,cm$ dimensionless lying on the largest base. It is now made to stand with length vertical. If $g=10 \,ms ^{-2}$, then the amount of work done is

Work, Energy and Power

Solution:

Initial height of $CG =4\, cm$
Final height of $CG =10 \, cm$
Increase in height $=6 \, cm =0.06\, m$
Work done $=5 \times 10 \times 0.06=3\, J$