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  4. A 5.82 g silver coin is dissolved in nitric acid. When sodium chloride is added to the solution, all the silver is precipitated as AgCl . The AgCl precipitate weighs 7.20 g . The percentage of silver in the coin is

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Q. A $ 5.82 \,g $ silver coin is dissolved in nitric acid. When sodium chloride is added to the solution, all the silver is precipitated as $ AgCl $ . The $ AgCl $ precipitate weighs $ 7.20\, g $ . The percentage of silver in the coin is

AMUAMU 2014Some Basic Concepts of Chemistry

Solution:

Silver solution in $HNO_{3}+NaCl \to \underset{108+35.5}{AgCl} $
Atomic mass of $Ag = 108\, g =143.5$
Weight of $Ag = 5.82 \,g$
$\because$ $143.5\,g\, AgCl$ is obtained from $Ag = 108 \,g$
$\therefore 7.20\,g\,AgCl$ will be obtained from $Ag$
$=\frac{108\times 7.20}{143.5}=5.418\,g$
Weight of $Ag$ taken $=5.82$
$\%$ purity $=\frac{5.418}{5.82}\times100$
$=93.09\%$