Thank you for reporting, we will resolve it shortly
Q.
A $5.0 \,mL$ solution of $H _{2} O _{2}$ liberates $1.27 \,g$ of iodine from an acidified $KI$ solution. The percentage strength of $H _{2} O _{2}$ is
Hydrogen
Solution:
$H _{2} O _{2} \equiv I _{2}$
$2 KI + H _{2} O _{2}+ H _{2} SO _{4} \rightarrow K _{2} SO _{4}+2 H _{2} O + I _{2}$
$mEq$ of $H _{2} O _{2}=5 \times N$
$mEq of _{2}=\frac{\text { Weight }}{\text { E.w }} \times 1000$
$\frac{1.27}{127} \times 1000=10 mEq \therefore mEq$ of $H _{2} O _{2}= mEq$ of $I _{2}$
$5 \times N =10 \therefore N =2$
$1 \,N$ of $H _{2} O _{2}=1.7 \%$ of $H _{2} O _{2}$
$2 \,N$ of $H _{2} O _{2}=3.4 \% H _{2} O _{2}$