Question

$A \xrightarrow{ 4KOH, O_{2}} 2 \underset{\text{ (Green)}}{\underline{B}} + 2 H_2O $
$ 3 \underline{B} \xrightarrow{4 HCl} \underset{\text{ (Purple)}}{ 2 \underline{C} }+ MnO_2 + 2H_2O$
$2 \underline{B} \xrightarrow {H_2 O, KI} 2 \underline{A} + 2 KOH + \underline{D} $ In the above sequence of reactions, $\underline{A}$ and $\underline{D}$ respectively, are :-

• A. $KIO_3$ and $MnO_{2}$
• B. KI and $K_2 MnO_{4}$
• C. $MnO_2 $ and $KIO_3$
• D. KI and $K MnO_{4}$

Answer 1

Answer: (C)

$MnO _{2}( A ) \xrightarrow{4 KOH , O _{2}} 2 K _{2} MnO _{4}( B )+2 H _{2} O$
$($ Green $)$
$3 K _{2} MnO _{4}( B ) \xrightarrow{4 HCl } 2 KMnO _{4}( C )+2 H _{2} O$
(Purple)
$2 KMnO _{4}( C ) \xrightarrow{ H _{2} O , Kl } 2 MnO _{2}( A )+2 KOH +$
$KIO _{3}( D )$
$A \rightarrow MnO _{2}$
$D \rightarrow KIO _{3}$