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Q.
A $400\, mg$ iron capsule contains $100\, mg$ of ferrous fumarate, $(CHCOO)_2Fe$. The percentage of iron present in it, is approximately
Some Basic Concepts of Chemistry
Solution:
Molecular wt. of $(CHCOO)_2Fe = 170$
Fe present in 100 mg of $(CHCOO)_2Fe$
$=\frac{56}{170}\times100\,mg=32.9\,mg$
This is present in $400\, mg$ of the capsule
$\therefore \%$ of Fe in the capsule $=\frac{32.9}{400}\times100=8.2$