Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A 4 : 1 mixture of helium and methane is contained in a vessel at 10 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. The composition of the mixture effusing out initially is

JIPMERJIPMER 2014States of Matter

Solution:

Pressure of helium = $8\, bar, CH_4 = 2\, bar$
According to Graham’s law,
$\frac{r_{1}}{r_{2}}=\frac{P_{1}}{P_{2}} \sqrt{\frac{M_{2}}{M_{1}}} $
$\frac{r_{He}}{r_{CH_4}} =\frac{P_{1}}{P_{2}} \sqrt{\frac{M_{CH_4}}{M_{He}}} =\frac{8}{2} \sqrt{\frac{16}{4} } =\frac{8}{1} =8 : 1$