Thank you for reporting, we will resolve it shortly
Q.
A $3p$ orbital has:
Structure of Atom
Solution:
Total nodes$= n - 1$
No. of radial nodes $= n - 1 - 1$
No. of angular nodes $= l$
For 3p sub-shell, $n = 3, l = 1$
$\therefore $ No. of radial nodes $= n - l - 1 = 3 - 1 - 1 = 1$
$\therefore $ No. of angular nodes $= l = 1$