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  4. A 30 g bullet travelling initially at 500 ms-1 penetrates 12 cm into wooden block. The average force exerted will be

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Q. A 30 g bullet travelling initially at 500 $ms^{-1}$ penetrates 12 cm into wooden block. The average force exerted will be

Work, Energy and Power

Solution:

From kinetic energy relation
$\frac{1}{2}mv^2=F.s$
or $F=\frac{mv^2}{2s}$
$\frac{30 \times 10^{-3} \times (500)^2}{2 \times 12\times 10^{-2}}$
31250 N