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  4. A 2kg stone tied at the end of a string 1m long is whirled along a vertical circle at a constant speed of 4 ms- 1 . What will be the tension in the string (in newton) at the bottom-most point?

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Q. A $2kg$ stone tied at the end of a string $1m$ long is whirled along a vertical circle at a constant speed of $4 \, ms^{- 1}$ . What will be the tension in the string (in newton) at the bottom-most point?

NTA AbhyasNTA Abhyas 2022

Solution:

Here, $m=2 \, kg,r=1 \, m,v=4 \, ms^{- 1}$
Tension at the bottom of the circle,
$T_{L}=mg+\frac{m v^{2}}{r}$
$=20+\frac{2 \times 4^{2}}{1}=52\,N$