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  4. A 280 ohm electric bulb is connected to 200 V electric line. The peak value of current in the bulb will be

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Q. A $280$ ohm electric bulb is connected to $200 \,V$ electric line. The peak value of current in the bulb will be

Alternating Current

Solution:

$i_{ ms }=\frac{200}{280}=\frac{5}{7} A .$
So $i_{0}=i_{ rms }' \times \sqrt{2}$
$=\frac{5}{7} \times \sqrt{2} \approx 1 A$