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Q. A 25,000 Da protein contains a single binding site for a molecule (ligand), whose molecular weight is 2,500 Da. Assuming high affinity and physiologically irreversible binding, the amount of the ligand required to occupy all the binding sites in 10 mg protein will be

KVPYKVPY 2017

Solution:

Assuming $x$ as the amount of ligand to occupy all the binding sites in 10 mg protein.
$\frac{x mg} {Protein\, in\, grams}$ $= \frac{Ligand\, molecular\, weight}{Protein molecular weight}$
$x=\frac{2500}{25000}\times 10=1mg$