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Q. A $220\, volt, 1000\, watt$ bulb is connected across a $110\, volt$ mains supply. The power consumed will be

AIEEEAIEEE 2003Current Electricity

Solution:

$P_{consumed}=\frac{V^{2}}{R}=\frac{\left(110\right)^{2}}{\left(220\right)^{2}/1000 }=250$ watt.