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Q. A 220 volt - 1000 watt bulb is connected across a 110 volt mains supply. The power consumed will be

JIPMERJIPMER 2016Current Electricity

Solution:

Resistance of bulb, $R = \frac{\left(220\right)^{2}}{1000} = \frac{484 }{10}\Omega$
$\because$ New supplied voltage = 110 V
$\therefore $ Power consumed by it, $P = \frac{V^2}{R} $
$= \frac{(110)^2}{484} \times 10$
= 250 watt