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Q. A 20 kg block is initially at rest on a rough horizontal surface. A horizontal force of 75 N is required to set the block in motion. After it is in motion, a horizontal force of 60 N is required to keep the block moving with constant speed. The coefficient of static friction is

AMUAMU 1999

Solution:

: $ F=\mu R=\mu Mg $ $ 75=\mu \times 20\times 10 $ for static friction $ \mu =\frac{75}{200}=0.38 $