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  4. A 20.0 mL solution of Na 2 CO 3 required 30 mL of 0.01 M K 2 Cr 2 O 7 solution for the oxidation to Na 2 SO 4 ⋅ Hence, molarity of Na 2 SO 3 solution is

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Q. A $20.0\, mL$ solution of $Na _2 CO _3$ required $30\, mL$ of $0.01\, M\, K _2 Cr _2 O _7$ solution for the oxidation to $Na _2 SO _4 \cdot$ Hence, molarity of $Na _2 SO _3$ solution is

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Solution:

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$N_1 V_1\left( So _3^{2-}\right)=N_2 V_2\left( Cr _2 O _7^{2-}\right)$
$2 M_1 \times 20=6 \times 0.01 \times 30$
$M_1=0.045 \,M$