1. Tardigrade
  2. Question
  3. Physics
  4. A 2 μ F capacitor C 1 is first charged to a potential difference of 10 V using a battery. Then the battery is removed and the capacitor is connected to an uncharged capacitor C 2 of 8 μ F. The charge in C 2 on equilibrium condition is μ C . (Round off to the Nearest Inteorer) <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/b2f82d1f2d2bc2cba34635d39199d603-.png />

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A $2 \mu\,F$ capacitor $C _{1}$ is first charged to a potential difference of $10\,V$ using a battery. Then the battery is removed and the capacitor is connected to an uncharged capacitor $C _{2}$ of $8 \mu\,F$. The charge in $C _{2}$ on equilibrium condition is_______ $\mu\,C .$
(Round off to the Nearest Inteorer)
image

JEE MainJEE Main 2021Electrostatic Potential and Capacitance

Solution:

$20=\left( C _{1}+ C _{2}\right) V \Rightarrow V =2$ volt.
$Q _{2}= C _{2} V =16 \mu C$
$=16$