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Q.
$\left(\frac{A^{2}}{\text { Mass }}\right)$ has the dimensions of kinetic energy. Then $A$ has the dimensions of
Physical World, Units and Measurements
Solution:
$\frac{A^{2}}{\operatorname{Mass}(m)}= KE =\frac{1}{2} m v^{2}$
or $A^{2}=\frac{1}{2} m^{2} v^{2}$
$\therefore A$ has the dimensions of $m v=\left[ MLT ^{-1}\right]$ which are the dimensions of impulse $(F \times t)$.