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Q. A $2\,m$ long tube closed at one end is lowered vertically into water until the closed end is flush with the water surface, Calculate $h$ as shown in the following figure:
image
(Barometric pressure $=1 \,atm =10\, m$ of hydrostatic water head, temperature $=25^{\circ} C$, density of water $=1 \,g / ml$, neglect water vapour pressure)

States of Matter

Solution:

Let the cross section area be $a$ now as per Boyle's law
$P _{1} V_{1}=P_{2} V_{2} $
$(10+h) h \times a=10 \times 2 \times a $
$\Rightarrow 10 h+h^{2}=20$
$ \Rightarrow h=1.71\, m$