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Q. $A_{2}B$ has antifluorite structure ( $\text{B}$ forms $\text{FCC}$ lattice and $\text{A}$ occupies tetrahedral voids). If all ions along any one body diagonal are removed, then new formula of compound will be:

NTA AbhyasNTA Abhyas 2020The Solid State

Solution:

On one body diagonal, $2 A$ atoms(full contribution) $2 B$-atoms $\frac{1}{8}$ contributions lie. So, new formula $=$ $A_{8-2} B_{4-\frac{1}{4}}=A_8 B_5$