Question

A 2.5 mol sample of hydrazine, $ {{N}_{2}}{{H}_{4}} $ loses 25 mole of electrons in being converted to a new compound $ X $ . Assuming that all of the nitrogen appears in the new compound, what is the oxidation state of nitrogen in compound $ X $ ?

• A. $ -1 $
• B. $ -2 $
• C. $ +3 $
• D. $ +4 $

Answer 1

Answer: (C)

Oxidation number of N in $ {{N}_{2}}{{H}_{4}},-2 $ Number of electrons lost by each N atom $ =\frac{25}{2\times 2.5}=5 $ Then, $ x-(-2)=5 $ or $ x=+3 $