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  4. A 2.5 m long straight wire having mass of 500 g is suspended in mid air by a uniform horizontal magnetic field B. If a current of 4 A is passing through the wire then the magnitude of the field is (Take g=10 m s-2)

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Q. $A$ $2.5\, m$ long straight wire having mass of $500\, g$ is suspended in mid air by a uniform horizontal magnetic field $B$. If a current of $4\, A$ is passing through the wire then the magnitude of the field is (Take $g=10\, m\, s^{-2})$

Moving Charges and Magnetism

Solution:

Here, $m=500\,g =0.5\, kg$,
$I=4\,A$,
$l=2.5\,m$
As $F=IlBsin\theta $
$mg=IlB\, sin\,90^{\circ}$, $(\because \theta=90^{\circ}$ and $F=mg)$
$\therefore B=\frac{mg}{Il}=\frac{0.5\times10}{4\times2.5}=0.5\,T$