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  3. Chemistry
  4. A 2.24 L cylinder of oxygen at N.T.P. is found to develop a leakage. When the leakage was plugged, the pressure dropped to 570 mm of Hg. The number of moles of gas that escaped will be

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Q. A $2.24\, L$ cylinder of oxygen at $N.T.P$. is found to develop a leakage. When the leakage was plugged, the pressure dropped to $570\, mm$ of $Hg$. The number of moles of gas that escaped will be

States of Matter

Solution:

No. of moles originally present $=\frac{2.24}{22.4}=0.1$

After leakage, $P V=n R T$

or $n=\frac{P V}{R T}=\frac{(570 / 760)(2.24)}{0.0821 \times 273}=0.075$

Hence, no. of moles leaked out $=0.1-0.075=0.025\, mol$