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Q. A $2 \times 2$ matrix is formed with entries from the set $\{0,1\}$. The probability that it is singular, is

Probability - Part 2

Solution:

Number of non singular determinant
$=\begin{bmatrix}1 & 0 \\ 1 & 1\end{bmatrix},\begin{bmatrix}1 & 1 \\ 0 & 1\end{bmatrix},\begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix},\begin{bmatrix}0 & 1 \\ 1 & 0\end{bmatrix},\begin{bmatrix}1 & 1 \\ 1 & 0\end{bmatrix},\begin{bmatrix}0 & 1 \\ 1 & 1\end{bmatrix}$
$\therefore P ($ singular $)=1- P ($ Non-Singular $)=1-\frac{6}{16}=\frac{5}{8}$.