1. Tardigrade
  2. Question
  3. Physics
  4. A 16 Ω wire is bend to form a square loop. A 9 V supply having internal resistance of 1 Ω is connected across one of its sides. The potential drop across the diagonals of the square loop is × 10-1 V

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A $16\, \Omega$ wire is bend to form a square loop. A $9\, V$ supply having internal resistance of $1\, \Omega$ is connected across one of its sides. The potential drop across the diagonals of the square loop is_______ $\times 10^{-1} V$

JEE MainJEE Main 2021Current Electricity

Solution:

here assume current as
image
By KVL in outer loop
$9-12 i-4 i=0$
$16 i=9$
$8 i=\frac{9}{2}=4.5$
$=45 \times 10^{-1}$