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Q. A $100 \, V$ , AC source of frequency $500 \, Hz$ is connected to an LCR circuit with $L=8.1 \, mH$ , $C \, = \, 12.5 \, \mu F, \, R \, = \, 10 \, \Omega$ all connected in series as shown in the figure. What is the quality factor of the circuit?
Question

NTA AbhyasNTA Abhyas 2022

Solution:

In the condition of resonance , quality factor
$Q=\frac{1}{R}\sqrt{\frac{L}{C}}$ $= \, \frac{1}{10} \, \sqrt{\frac{8.1 \times 10^{- 3}}{12.5 \times 10^{- 6}}}$
$=2.54$