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Q. A $100$ turn closely wound circular coil of radius $ 10\,cm $ carries a current of $ 3.2\,A $ . The magnetic moment of the coil is, approximately

J & K CETJ & K CET 2011Moving Charges and Magnetism

Solution:

Magnetic moment,
$ M=niA $
$ M=100\times 3.2\times (\pi r_{1}^{2}) $
$ =100\times 3.2\times \frac{22}{7}\times \frac{10}{100}\times \frac{10}{100} $
$ =10.048\,A-m^{2} $