Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A $100 g$ of a sample of haemoglobin on analysis was found to contain $0.34 \%$ Fe by mass. If each haemoglobin molecule has four $Fe ^{2+}$ ions, the molecular mass of haemoglobin is- $( Fe =56 \,amu )$

Some Basic Concepts of Chemistry

Solution:

$100 \,g$ Haemoglobin contains $F e=0.34\, g $

1 mole haemoglobin contains $Fe =4$ mole $Fe ^{2+}$

$=4 \times 56=224 \,g$

$0.34 \,g \,Fe$ is present in haemoglobin $=100 g$

$224 \,g $ Fe is present in haemoglobin $=\frac{100}{0.34} \times 224 $

$=65882\, g$