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  2. Question
  3. Chemistry
  4. A 10 L box contains O 3 and O 2 at equilibrium at 2000 K. KP=4.17 × 1014 atm for 2 O 3 leftharpoons 3 O 2 . Assume that P O 2 > > P O 3 and if total pressure is 7.33 atm, then partial pressure of O 3 will be

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Q. A $10\, L$ box contains $O _{3}$ and $O _{2}$ at equilibrium at $2000\, K$.
$K_{P}=4.17 \times 10^{14}$ atm for $2 O _{3} \rightleftharpoons 3 O _{2} .$ Assume that $P_{ O _{2}} > > P_{ O _{3}}$ and if total pressure is $7.33\, atm$, then partial pressure of $O _{3}$ will be

Equilibrium

Solution:

$K_{p}=4.17 \times 10^{14}=\frac{\left(P_{ O _{2}}\right)^{3}}{\left(P_{ O _{3}}\right)^{2}}$
$\therefore P_{ O _{2}} > > P_{ O _{3}}$
$\therefore P_{ O _{2}}+P_{ O _{3}}=7.33$
or $P_{ O _{2}}=7.33$
$\therefore P_{ O _{3}}=\sqrt{\frac{(7.33)^{3}}{4.17 \times 10^{14}}}$
$=9.71 \times 10^{-7}$ atm