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Q. A 10 kg boy standing in a 40 kg boat floating on water is 20 m away from the shore of the river. If the boy moves 8 m on the boat towards the shore, then how far is he from the shore? (Assume no friction between boat and water)

System of Particles and Rotational Motion

Solution:

Let the boat moves a distance $x$ away from shore.
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Then net displacement of boy towards shore $=8-x$
Now apply: $m_{1} x_{1}=m_{2} x_{2}$
$\Rightarrow 40 x=10(8-x) \Rightarrow x=1.6\,m$
Distance of boy from shore $=20-(8-x)=13.6 \,m$