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Q. A 10 cm long wire is placed horizontally on the surface of water and is gently pulled up with a force of $ 2\times {{10}^{-2}}N $ to keep the wire in equilibrium. The surface tension, in $ N{{m}^{-1}} $ of water is

AMUAMU 1999

Solution:

: $ S2l=F $ (where S is surface tension) Or $ S=\frac{F}{2l}=\frac{2\times {{10}^{-2}}}{2\times 0.1}N{{m}^{-1}}=0.1\,N{{M}^{-1}} $