Question

A $10\, cm ^{3}$ cube floats in water with a height of $4\, cm ^{3}$ remaining above the surface. The density of the material from which the cube is made is

• A. $0.6\, g\, cm ^{-3}$
• B. $1.0\, g\, cm ^{-3}$
• C. $0.4\, g\, cm ^{-3}$
• D. $0.24\, g\, cm ^{-3}$

Answer 1

Answer: (A)

$\frac{\text{Volume of cube submerged}}{\text{Total volume}}$
$=\frac{\text { density of cube material }}{\text { density of water }}$
$\Rightarrow \frac{10-4}{10}=\frac{d}{1}$
$\therefore d=\frac{6}{10}=0.6\, g\, cm ^{-3}$