1. Tardigrade
  2. Question
  3. Physics
  4. A 1 kg stationary bomb is exploded in three parts having mass 1: 1: 3 respectively. Part having same mass move in perpendicular direction with velocity 30 m/s, then the velocity of bigger part will be

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A $1 \,kg$ stationary bomb is exploded in three parts having mass $1 : 1 : 3$ respectively. Part having same mass move in perpendicular direction with velocity $30 \,m/s$, then the velocity of bigger part will be

AIPMTAIPMT 2001Laws of Motion

Solution:

Apply conservation of linear momentum.
Total momentum before explosion = total momentum after explosion
$0=\frac{m}{5}v_1\vec i+\frac{m}{5}v_2\vec j+\frac{3m}{5}\vec{v_3};$
$\frac{3m}{5}\vec{v_3}=-\frac{m}{5}[v_1\vec i+v_2\vec j]$
$\vec{v_3}=\frac{-v_1}{3}\vec i-\frac{v_2}{3}\hat j$
$\because v_1=v_2=30 \,m/\sec.$
$\vec{v_3}=-10\vec i-10\vec j; v_3$
$=10\sqrt2 \,m/ \sec.$