Question

A $1.0 \, \mu F$ capacitor is charged by a $40.0 \,V$ power supply. The fully charged capacitor is then discharged through a $10.0- mH$ inductor. The maximum current in the resulting oscillations (in $mA$ ) is___

Answer 1

At different times, $\left(U_{C}\right)_{\max }=\left(U_{L}\right)_{\max }$,
so $\left[\frac{1}{2} C(\Delta V)^{2}\right]_{\max }=\frac{1}{2} L l_{i}^{2}$
Then, $I_{i}=\sqrt{\frac{C}{L}}(\Delta V)_{\max }$
$=\sqrt{\frac{1.00 \times 10^{-6} F }{10.0 \times 10^{-3} H }}(40.0 \,V )$
$=0.400 \,A =400 \,mA$