1. Tardigrade
  2. Question
  3. Chemistry
  4. A 0.1 molal aqueous solution of a weak acid is 30% ionized. If Kf for water is 1.86° C/m, the freezing point of the solution will be -

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Q. A 0.1 molal aqueous solution of a weak acid is 30% ionized. If $K_f$ for water is $ 1.86^{\circ} C/m$, the freezing point of the solution will be -

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Solution:

$i = 1 - \alpha + n\alpha$
$ i = 1 - 0.3 + 2 (0.3)$
$i = 1.3$
$ \Delta T_f = iK_f m$
$ = 1.3 \times 1.86 \times 0.1$
$\Delta T_f = + 0.24^{\circ} C$
Freezing point of solution = - 0.24ºC