1. Tardigrade
  2. Question
  3. Chemistry
  4. A 0.1 molal aqueous solution of a weak acid is 30 % ionised. If Kf for water is 1.86° C/m, the freezing point of the solution will be

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Q. A $0.1$ molal aqueous solution of a weak acid is $30 \%$ ionised. If $K_f$ for water is $1.86^{\circ} C/m,$ the freezing point of the solution will be

VITEEEVITEEE 2012

Solution:

Freezing point depression $\left(\Delta T_{f}\right)=i K_{f} m$
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$ \therefore \Delta T_{f} =1.3 \times 1.86 \times 0.1=0.2418^{\circ} C $
$ T_{f} =0-0.2418^{\circ} C $
$=-0.2418^{\circ} C $