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  4. A 0.1 kg mass is suspended from a wire of negligible mass. The length of the wire is 1 m and its cross-sectional area is 4.9×10-7 m2. If the mass is pulled a little in the vertically

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Q. A $0.1\, kg$ mass is suspended from a wire of negligible mass. The length of the wire is $1\, m$ and its cross-sectional area is $4.9\times10^{-7} m^2$. If the mass is pulled a little in the vertically

Oscillations

Solution:

$\omega=\sqrt{\frac{K}{m}}=\sqrt{\frac{YA}{lm}}=\sqrt{\frac{(n\times10^9)(4.9\times10^{-7})}{1\times0.1}}$
Putting, $\omega=140$ rad $s^{-1}$ in above equation we get, n=4