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  4. 99% of a first order reaction was completed in 32min. When will 99.9% of the reaction complete ?

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Q. 99% of a first order reaction was completed in 32min. When will 99.9% of the reaction complete ?

Chemical Kinetics

Solution:

$k =\frac{2.303}{t} \log \frac{100}{100-x}$
Substituting the values,
$k=\frac{2.303}{32} \log \frac{100}{1}$
$k = 0 . 1 4 4 \min ^{-1}$
$t=\frac{2.303}{0.144} \log \frac{100}{0.1}$
$t = 4 8 ~ m i n$