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  4. 99 % of a first order reaction was completed in 32 min. When will 99.9 % of the reaction complete?

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Q. $99 \%$ of a first order reaction was completed in $32 \min$. When will $99.9 \%$ of the reaction complete?

ManipalManipal 2018

Solution:

$k=2.30332 \log \frac{a}{a-0.99 a}=0.1439 \min ^{-1}$
$t=\frac{2.303}{0.1439} \log \frac{a}{a-0.999 a}=48 \min$