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Q. $9.2$ grams of $N_{2}O_{4(g)}$ is taken in a closed one litre vessel and heated till the following equilibrium is reached $N_{2}O_{4(g)} \rightleftharpoons 2NO_{2(g)}.$
At equilibrium, $50\% N_{2}O_{4(g)}$ is dissociated. What is the equilibrium constant (in mol litre-1) (Molecular weight of $N_{2}O_{4} = 92$)?

Equilibrium

Solution:

$K_{c}=\frac{\left[NO_{2}\right]^{2}}{\left[N_{2}O_{4}\right]}=\frac{4\times\left(0.05\right)^{2}}{0.05}=4 \times0.05 =0.2$