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  4. 8g of NaOH is dissolved in 18g of H2O. Mole fraction of NaOH in solution and molality (in mol kg-1) of the solutions respectively are :

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Q. $8g$ of $NaOH$ is dissolved in $18g$ of $H_2O$. Mole fraction of $NaOH$ in solution and molality (in mol $kg^{-1})$ of the solutions respectively are :

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Solution:

$8g\, NaOH$, mol of $NaOH$ = $\frac{8}{40} \, = \, 0.2 mol$
$18g\, H_2O$, mol of $H_2O$ = $\frac{18}{18} \, = 1 mol$
$\therefore \, \, \, \, X_{NaOH} \, \, = \, \, \frac{0.2}{1.2} \, = \, 0.167$
$Molality \, = \, \frac{0.2 \times \, 1000}{18} \, \, =11.11\,m$