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Q. $80g$ of water at $30^\circ C$ are poured on a large block of ice at $0^\circ C.$ The mass of ice that melts is:-

NTA AbhyasNTA Abhyas 2020

Solution:

$ms\Delta \theta =m^{'}L$
$80\times 1\times \left(30 - 0\right)=m^{'}\times 80$
$m^{'}=30g$