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Q. $80 \, g$ of water at $30 \,{}^\circ C$ is poured on a large block of ice at $0 \,{}^\circ C$ . The mass of ice that melts is

NTA AbhyasNTA Abhyas 2020

Solution:

$m_{i c e} \, L=m_{w}S\Delta Q$
$m_{i c e}\left(80\right)=80\left(1\right)\left(30 - 0\right)$
$m_{i c e}=30 \, g$