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Q.
$7$ mole of certain monoatomic ideal gas undergoes a temperature increase of $40\, K$ at constant pressure. The increase in the internal energy of the gas in this process is (Given $R =8.3\, JK ^{-1}\, mol ^{-1}$ )
For a quasi-static process the change in internal energy of an ideal gas is
$\Delta U = nC _{ V } \Delta T $
$ = n \times \frac{3 R }{2} \times \Delta T$
[molar heat capacity at constant volume for mono atomic gas $=\frac{3 R }{2}$ ]
$\Delta U =7 \times \frac{3}{2} \times 8.3 \times 40=3486 \,J$