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Q.
7 digits from the number $1, 2, 3, 4, 5, 6, 7, 8, 9$ are written in a random order (without repetation). The
chance that the 7 digit number is divisible by 9 is :
Probability - Part 2
Solution:
$n ( S )={ }^9 C _7 \cdot 7 !$
$n ( A )=4 \cdot 7 !$
$\frac{4 \cdot 7 !}{{ }^9 C _7 \cdot 7 !}=\frac{4}{36}$
$\therefore P ( A )=\frac{4}{36}=\frac{1}{9}$